Subject Creating and inserting GUIDs
Author Steve_Miller@sil.org
In a message from David Garamond awhile ago, he said he has a GUID defined
as CHAR(16) CHARACTER SET OCTETS. Well and good. Now how do I go about
inserting this value into my new guid field?:

'8645FA4B-EE90-11D2-A9B8-0080C87B6086'

Also, while I'm at it, does anyone know where I can find a GUID generator
for Firebird? I want something that replaces the NEWID() function of SQL
Server.

Steve Miller
Language Software Development
SIL International

[Non-text portions of this message have been removed]