Subject | Re: [firebird-support] How do I count the number of duplicate rows in a table? |
---|---|
Author | Tim Ward |
Post date | 2014-10-28T12:20:37Z |
SELECT CASE_NUMBER, COUNT(*) FROM
ACCT_CASE_COURT GROUP BY CASE_NUMBER
That what you want? (The sorting comes for free.)
On 28/10/2014 12:13, 'Softtech Support' stwizard@... [firebird-support] wrote:
That what you want? (The sorting comes for free.)
On 28/10/2014 12:13, 'Softtech Support' stwizard@... [firebird-support] wrote:
Greetings All,Firebird 1.5.3Should be elementary but, I'm drawing a blank on how to accomplish this.I have a table (ACCT_CASE_COURT) that contains these fields (among others):ACCT_CASE_COURT_ID INTEGER NOT NULL PKACCT_ID INTEGER NOT NULLCASE_ID SMALLINT NOT NULLCASE_NUMBER VARCHAR(20) NOT NULL...How do I form a SQL Select statement that would contain CASE_NUMBER in the first column (sorted) and number of times that the case number is found in the table in the second column (CNT)?Any help truely appreciated.Thanks,Mike
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