Subject | Re: [firebird-support] How do I count the number of duplicate rows in a table? |
---|---|
Author | Martijn Tonies (Upscene Productions) |
Post date | 2014-10-28T12:18:05Z |
select count(case_number) as counted, case_number
from ACCT_CASE_COURT
group by case_number
?
With
regards,
Martijn Tonies
Upscene Productions
http://www.upscene.com
Download Database Workbench for Oracle, MS SQL Server, Sybase SQL
Anywhere, MySQL, InterBase, NexusDB and Firebird!
Martijn Tonies
Upscene Productions
http://www.upscene.com
Download Database Workbench for Oracle, MS SQL Server, Sybase SQL
Anywhere, MySQL, InterBase, NexusDB and Firebird!
Sent: Tuesday, October 28, 2014 1:13 PM
Subject: [firebird-support] How do I count the number of duplicate
rows in a table?
Greetings All,
Firebird 1.5.3
Should be elementary but, I'm drawing a blank on
how to accomplish this.
I have a table (ACCT_CASE_COURT) that contains
these fields (among others):
ACCT_CASE_COURT_ID
INTEGER NOT NULL PK
ACCT_ID INTEGER
NOT NULL
CASE_ID
SMALLINT NOT NULL
CASE_NUMBER
VARCHAR(20) NOT NULL
...
How do I form a SQL Select statement that would
contain CASE_NUMBER in the first column (sorted) and number of times that the
case number is found in the table in the second column (CNT)?
Any help truely appreciated.
Thanks,
Mike
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