Subject | Re: Extract Fk dependant columns |
---|---|
Author | javakqj |
Post date | 2009-11-17T21:53:19Z |
I see some double quotes(") in the following lines , remove them and the query should run. Or if you could post the exact error it would be
help.
and d1.RDB$DEPENDENT_TYPE = 2 "
AND rc.RDB$RELATION_NAME = 'MY_TABLE' "
AND rc.RDB$CONSTRAINT_NAME = 'MY_FK' "
-JD
help.
and d1.RDB$DEPENDENT_TYPE = 2 "
AND rc.RDB$RELATION_NAME = 'MY_TABLE' "
AND rc.RDB$CONSTRAINT_NAME = 'MY_FK' "
-JD
--- In firebird-support@yahoogroups.com, mourad@... wrote:
>
> Hello everybody,
> I've developped an application whitch updates the data of my database. Fore that, I must drop the Foreign keys and when I finish I create them.
> From http://www.alberton.info/firebird_sql_meta_info.html, I've taken inforation how to get the Foreign key details but it wasen't very helpfull.
> Sothat I've traied to divise my operations and I've the following queries :
> 1) To have the table's FK :
> SELECT rc.RDB$CONSTRAINT_NAME AS fk_name, refc.RDB$DELETE_RULE AS on_del, refc.RDB$UPDATE_RULE AS on_upd
> FROM RDB$RELATION_CONSTRAINTS rc
> LEFT JOIN RDB$REF_CONSTRAINTS refc ON rc.RDB$CONSTRAINT_NAME = refc.RDB$CONSTRAINT_NAME
> WHERE rc.RDB$CONSTRAINT_TYPE = 'FOREIGN KEY'
> AND rc.RDB$RELATION_NAME = 'MY_TABLE'
> 2) To have the column on whitch the FK is applied :
> select RDB$FIELD_NAME from RDB$INDEX_SEGMENTS where RDB$INDEX_NAME = 'MY_TABLE' order by RDB$FIELD_POSITION
>
> 3)To have dependant table of every FK :
> ELECT rc.RDB$RELATION_NAME AS PARENT
> FROM RDB$RELATION_CONSTRAINTS a
> JOIN RDB$INDICES b ON (b.RDB$INDEX_NAME=a.RDB$INDEX_NAME)
> JOIN RDB$RELATION_CONSTRAINTS rc ON rc.rdb$index_name=b.rdb$foreign_key
> WHERE a.RDB$CONSTRAINT_TYPE='FOREIGN KEY'
> AND a.RDB$RELATION_NAME = 'MY_TABLE'
> and a.RDB$INDEX_NAME = 'MY_FK'
>
> 4)And for having the dependant column(s) :
> SELECT DISTINCT d1.RDB$FIELD_NAME AS ref_field
> FROM RDB$RELATION_CONSTRAINTS rc
> JOIN RDB$INDICES b ON (b.RDB$INDEX_NAME = rc.RDB$INDEX_NAME)
> JOIN RDB$RELATION_CONSTRAINTS a ON (a.rdb$index_name = b.rdb$foreign_key)
> inner JOIN RDB$DEPENDENCIES d1 ON d1.RDB$DEPENDED_ON_NAME = a.RDB$RELATION_NAME
> WHERE rc.RDB$CONSTRAINT_TYPE = 'FOREIGN KEY'
> and d1.RDB$DEPENDENT_TYPE = 2 "
> AND rc.RDB$RELATION_NAME = 'MY_TABLE' "
> AND rc.RDB$CONSTRAINT_NAME = 'MY_FK' "
> AND a.RDB$RELATION_NAME = 'MY_DEPENDENT_TABLE'
>
> My problem is that the last query dont work fine. Can anyone tell me whete I'm wrong.
> Many thanks for your usefull help.
> Best regards.
> Mourad
>