Subject | Re: [firebird-support] Three integers to date |
---|---|
Author | Nick Upson |
Post date | 2003-06-27T08:33:26Z |
update table1
set new_datecol = cast (cast(day as char) ||'.'||cast(month as
char)||'.'||cast(year as char) as date)
(untested)
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set new_datecol = cast (cast(day as char) ||'.'||cast(month as
char)||'.'||cast(year as char) as date)
(untested)
>From: Martin <moirae@...>_________________________________________________________________
>Hi. Could anyone help me please. I've got date stored as three
>integers - day, month and year. Now I've added new date column and I
>am looking for any function (using FireBird, dialect 3) which can
>convert theese integers into date type.
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