Subject | select count(tbl.*), tbl.* |
---|---|
Author | esrefatak |
Post date | 2004-02-26T16:54:59Z |
Hi,
Feature request:
SQL:
SELECT
COUNT(sub_select.*) as COUNT, sub_select.user_name,
sub_select.password
FROM
(
SELECT
user_name, password
FROM
USER sub_select
WHERE
user_name LIKE '%%'
AND password LIKE '%%'
AND name LIKE '%%'
AND surname LIKE '%%'
)
Content of my "USER" table:
user_name password name surname
_________ ______ __________ ________
g aa aa
h bb bb
i cc cc
j dd dd
k ee ee
l ff ff
Result of SQL must be :
COUNT user_name password
_____ ______ __________
6 g aa
6 h bb
6 i cc
6 j dd
6 k ee
6 l ff
best regards
esref
Feature request:
SQL:
SELECT
COUNT(sub_select.*) as COUNT, sub_select.user_name,
sub_select.password
FROM
(
SELECT
user_name, password
FROM
USER sub_select
WHERE
user_name LIKE '%%'
AND password LIKE '%%'
AND name LIKE '%%'
AND surname LIKE '%%'
)
Content of my "USER" table:
user_name password name surname
_________ ______ __________ ________
g aa aa
h bb bb
i cc cc
j dd dd
k ee ee
l ff ff
Result of SQL must be :
COUNT user_name password
_____ ______ __________
6 g aa
6 h bb
6 i cc
6 j dd
6 k ee
6 l ff
best regards
esref