once again, thank you very much.

>
> Maybe this is what you're looking for (from the IBObjects help):
> <quote>
> Get the column of the grid from the column index of the dataset.
> Applies toTIB_CustomGrid
> Declaration: property GridCol[Index:integer]: integer;
> </quote>
>
> Have a look at the TIB_CustomGrid property GridFields, too.
> E.g. IB_Grid1.GridFields[0].FieldName should return the name of the field
> displayed in the first grid column.
> This is especially useful in a grid's OnDrawCell event where you need to
> know which field you have to draw.
>
> HTH,
> Markus

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