WITH TMP(ItemNr, FirstDate, LastDate) AS
(SELECT TTFirst.ItemNr, MAX(TTFirst.DateUsed), MAX(TTLast.DateUsed)
 FROM TEST_TABLE TTFirst
 JOIN TEST_TABLE TTLast ON TTFirst.ItemNr    = TTLast.ItemNr AND TTFirst.DateUsed <= TTLast.DateUsed
 WHERE NOT EXISTS(SELECT * FROM TEST_TABLE TTNot
                  WHERE TTFirst.ItemNr       = TTNot.ItemNr
                    AND TTFirst.DateUsed - 1 = TTNot.DateUsed)

   AND TTLast.DateUsed <= :MyEarlierDate

 GROUP BY 1)
SELECT ItemNr, LastDate, LastDate - FirstDate + 1 as ConsecutiveDays
FROM TMP

2017-03-06 7:44 GMT+01:00 'Stef' stef@... [firebird-support] <firebird-support@yahoogroups. com>:

Hi Set,

Your solution returns exactly what I am looking for. Much appreciated.

However when trying to query a snapshot for an earlier date, other than the
most recent day, seems problematic.

Stef van der Merwe


-----Original Message-----
From: firebird-support@yahoogroups.c om
[mailto:firebird-support@yahoo groups.com]

Sent: 03 March 2017 10:27 PM
To: firebird-support@yahoogroups.c om
Subject: Re: [firebird-support] QUERY QUESTION

Den 02.03.2017 17:36, skrev 'Stef' stef@... [firebird-support]:
> Good day,
>
> I have a question for you SQL boffins, how can I query a table to get
> the count of consecutive days found ?
>
> A Table contains rows with dates where an item(s) has been added for
> every day this item was used.
>
> i.e.
>
> itemnr                  dateused
>
> abc                         2017/02/01
> abc                         2017/02/02
> abc                         2017/02/25
> abc                         2017/02/25
> abc                         2017/02/25
> abc                         2017/02/26
> abc                         2017/02/27
> abc                         2017/02/28
> abc                         2017/03/01
> abc                         2017/03/02
>
> The result from above sample should be 6 as there is a break between
> 2017/02/02 and 2017/02/25?
Hi Stef, thanks for teaching me a new word, I've never heard 'boffin'
before!

I think your task roughly can be reformulated as:

I want to find the number of days from the most recent day of a record
without any record for the preceeding day to the most recent day for a
particular item, and add 1 to the result.

If so, this query will get you what you're asking for, although it may take
a while to return any result if the table is large:

WITH TMP(ItemNr, FirstDate, LastDate) AS (SELECT TTFirst.ItemNr,
MAX(TTFirst.DateUsed), MAX(TTLast.DateUsed)
  FROM TEST_TABLE TTFirst
  JOIN TEST_TABLE TTLast ON TTFirst.ItemNr    = TTLast.ItemNr
  WHERE NOT EXISTS(SELECT * FROM TEST_TABLE TTNot
                   WHERE TTFirst.ItemNr       = TTNot.ItemNr
                     AND TTFirst.DateUsed - 1 = TTNot.DateUsed)
  GROUP BY 1)
SELECT ItemNr, LastDate, LastDate - FirstDate + 1 as ConsecutiveDays FROM
TMP

So, what originally seems simple but grows complex once thinking about how
to solve it, happens to have a rather simple solution.

HTH,
Set

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------------------------------ ------
Posted by: "Stef" <stef@...>
------------------------------ ------

++++++++++++++++++++++++++++++ ++++++++++++++++++++++++++++++ ++++++

Visit http://www.firebirdsql.org and click the Documentation item
on the main (top) menu.  Try FAQ and other links from the left-side menu there.

Also search the knowledgebases at http://www.ibphoenix.com/resou rces/documents/

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