| Subject | AW: [firebird-support] Sequence |
|---|---|
| Author | Check_Mail |
| Post date | 2016-12-02T09:43:38Z |
Okay,
I would simply change the prio new in steps of 10.
Also I can do the following:
Priority in steps of 1
ID 10 Prio 1
ID 20 Prio 2
ID 23 Prio 3
ID 11 Prio 4
Now the user can Set the ID 23 to Prio 2, how can I realize this without a loop?
Update table set prio = newprio(1) where id = 20;
Update table set prio = prio – 1 where prio < newprio;
Update table set prio = prio + 1 where prio > newprio;
..more simplier?
Von: firebird-support@yahoogroups.com [mailto:firebird-support@yahoogroups.com]
Gesendet: Donnerstag, 1. Dezember 2016 18:47
An: firebird-support@yahoogroups.com
Betreff: RE: [firebird-support] Sequence
Olag,
> BeforeYou example is confusing.
> Record 1 prio 3
> Record 2 prio 10
> Record 3 prio 18
> Record 4 prio 20
> Record 5 prio 30
>
> The user set the record 4 to prio 15, I would like to do this:
>
> Record 1 from 3 to 10
> Record 2 from 10 to 20
> Record 3 from 20 (should 15, Destination between record 2 and record 3)) to
> 30
> Record 4 to 40
> Record 5 to 50
If a user can never change the position of Record 4 ahead of Record 3 (as is the case in your example) what purpose does priority serve.
If you had said that the outcome you wanted was:
Record 1 from 3 to 10
Record 2 from 10 to 20
Record 4 to 30 <-*********
Record 3 from 20 (should 15, Destination between record 2 and record 3)) to 40 <-*********
Record 5 to 50
Then that would have made sense.
Please clarify, the problem domain does matter to the solution.
Sean