|Subject||Re: [firebird-support] Age as a string and it\'s parts as integer|
|Author||Venus Software Operations|
Thanks a lot Martin will check it out and how it helps me with this function
On 07/01/2016 03:43 pm, Köditz, Martin Martin.Koeditz@... [firebird-support] wrote:
please have a look at Firebird’s EXTRACT functions.
select extract(year from CAST('1990-01-01' as Date)) from RDB$DATABASE;
returns 1990. Hope this helps.
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