i thing that u have some names with spaces at the beginning

use this select to find
select substring(upper(fname), count(*) from customer group by 1

Att,

Alexis Diel

On Sat, Aug 3, 2013 at 5:01 AM, Masotti Umberto <masotti@...> wrote:

> **
>
>
> Field fname is NOT NULL?
> count(*) value differs from count(fname) AFAIR.
>
> Inviato da iPad
>
> Il giorno 01/ago/2013, alle ore 16:20, "ASOrg" <asorg@...> ha
> scritto:
>
> >
> > Dear All
> >
> > select count(*) from customer ( returns 235384 )
> >
> > select count(*) from customer where substring(upper(fname) from 1 for 1
> ) in ('A','B','C',
> >
> 'D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z')
> ( returns 187671 )
> >
> > so there are 47.713 records whose fname started with letter A-Z.
> >
> > select distinct ascii_val(substring(upper(fname) from 1 for 1 )) from
> customer where substring(upper(fname) from 1 for 1 ) not in ('A','B','C',
> 'D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z')
> ( returns 0, 13, 46 )
> >
> > select count(*) from customer where ascii_val(substring(upper(fname)
> from 1 for 1 )) in (0,13,46) ( returns 38197 )
> >
> > I don't know how to find the other 9516 records.
> > Help please ?
> >
> > Thank you in advance
> >
> >
>
> [Non-text portions of this message have been removed]
>
>
>


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