Subject Re: [firebird-support] Solution for a redundant join?
Author Louis Kleiman (SSTMS, Inc.)
Try using aliases:

SELECT
SCHEDULE.DATE_TIME,
HOME_TEAM.TEAM as HomeTeamName,
AWAY_TEAM.TEAM as AwayTeamName
FROM
SCHEDULE
LEFT JOIN TEAMS HOME_TEAM ON SCHEDULE.HOME_TEAMID=HOME_TEAM.PRIMARYKEY
LEFT JOIN TEAMS AWAY_TEAM ON SCHEDULE.AWAY_TEAMID=AWAY_TEAM.PRIMARYKEY

On Wed, Oct 24, 2012 at 1:42 PM, Jeff <jeff_j_dunlap@...> wrote:

> **
>
>
> The following simple query produces the results below:
>
> SELECT SCHEDULE.DATE_TIME, TEAMS.TEAM FROM SCHEDULE
> LEFT JOIN TEAMS ON SCHEDULE.HOME_TEAMID=TEAMS.PRIMARYKEY
>
> ***QUERY RESULTS (Showing 'Home Team' Column)***
> 12/01/2012 TeamA
> 12/21/2012 TeamB
> 12/25/2012 TeamC
>
> How do I include the corresponding 'Away Team' column? Please see tables
> below:
>
> ***SCHEDULE TABLE***
> PRIMARYKEY HOME_TEAMID AWAY_TEAMID DATE_TIME
> 1 1 2 12/01/2012
> 2 2 3 12/21/2012
> 3 3 1 12/25/2012
>
> ***TEAMS TABLE***
> PRIMARYKEY TEAM_NAME
> 1 TeamA
> 2 TeamB
> 3 TeamC
>
> Please advise, thank you!
>
>
>


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