Subject | Re: [firebird-support] how to do a view (or work with) of top 80000 records |
---|---|
Author | Ann W. Harrison |
Post date | 2005-06-22T22:27:42Z |
Gary Benade wrote:
Regards,
Ann
>Do you have any idea what the performance of that is likely to be?
> ended up with this, based on your example
>
> select b.name, count(*) from customers c
> join branches b on b.orderappend = c.branchcode and b.enabled = 'T'
> where c.weighted_value >=
> (SELECT FIRST 1 SKIP 80000 Weighted_Value FROM Customers
> ORDER BY Weighted_Value DESC)
> group by 1
>
Regards,
Ann