Subject | Re: [firebird-support] difference in minutes |
---|---|
Author | Helen Borrie |
Post date | 2005-11-28T08:19:26Z |
At 08:06 AM 28/11/2005 +0000, you wrote:
isn't like the timer on your microwave, so you might also want to do a bit
more arithmetic to convert the decimal part to seconds, e.g. a result of
10.5000 is 10 mins + 30 seconds, not 10 mins + 50 seconds....
./heLen
>Hi folks,TIME type - TIME type = seconds; so just divide the result by 60. This
>
>I have two TIME fields in my table.
>
>How do i calculate an integer number which represents
>difference in minutes of these two values?
isn't like the timer on your microwave, so you might also want to do a bit
more arithmetic to convert the decimal part to seconds, e.g. a result of
10.5000 is 10 mins + 30 seconds, not 10 mins + 50 seconds....
./heLen