Subject | Re: SQL - Most recent order for each product |
---|---|
Author | ra8009 |
Post date | 2004-09-29T06:40:49Z |
Yes, you're right. From what I show here it's not needed. I actually
have the "real" query in descending order so I get the most recent
items at the top.
Now I just need to get rid of everything but the most recent/ highest
price. Do you know why the MAX in the HAVING doesn't accomplish that
ot what would work?
--- In firebird-support@yahoogroups.com, "Alan McDonald" <alan@m...>
wrote:
have the "real" query in descending order so I get the most recent
items at the top.
Now I just need to get rid of everything but the most recent/ highest
price. Do you know why the MAX in the HAVING doesn't accomplish that
ot what would work?
--- In firebird-support@yahoogroups.com, "Alan McDonald" <alan@m...>
wrote:
> > SELECTdefault.
> > DISTINCT
> > P.PRODUCT_ID,
> > O.ORDER_DATE,
> > ORDER_ITEM.PRICE
> >
> > FROM PRODUCTS P
> >
> > JOIN ORDER_ITEMS I
> > ON P.PRODUCT_ID = I.PRODUCT_ID
> >
> > JOIN ORDERS O
> > ON I.ORDER_ID = O.ORDER_ID
> >
> > JOIN CUSTOMER C
> > ON C.CUSTOMER_ID = O.CUSTOMER_ID
> >
> > WHERE
> > C.CUSTOMER_ID = 10300
> >
> > GROUP BY P.PRODUCT_ID, O.ORDER_DATE, I.PRICE
> > HAVING ORDER_DATE = MAX(ORDER_DATE)
> > ORDER BY 1,2
>
> correct me if I'm wrong but the group by clause will order by - by
> there's no need for the order by clause when you are grouping by
> Alan