Subject Re: [firebird-support] query performance problem
Author Tobias Jenkner
I am not quite shure if this is what you mean:

Plan:
PLAN (ITEM ORDER FK317B13C3E6B25E)

Adapted plan:
PLAN (ITEM ORDER FK317B13C3E6B25E)

Tobias.

Dimitry Sibiryakov wrote:
> On 6 Apr 2004 at 18:30, Tobias Jenkner wrote:
>
>
>>ALTER TABLE ITEM ADD PRIMARY KEY (ID);
>>
>>ALTER TABLE ITEM ADD CONSTRAINT FK317B1319BBD FOREIGN KEY (JOB)
>>REFERENCES JOB (ID);
>>ALTER TABLE ITEM ADD CONSTRAINT FK317B132AFA43C6 FOREIGN KEY
>>(INDEXCLASS) REFERENCES INDEX_CLASS (ID);
>>ALTER TABLE ITEM ADD CONSTRAINT FK317B13C3E6B25E FOREIGN KEY
>>(FINISHEDSTEP) REFERENCES STEP (ID);
>>
>>CREATE INDEX FK317B1319BBD ON ITEM (JOB);
>>CREATE INDEX FK317B132AFA43C6 ON ITEM (INDEXCLASS);
>>CREATE INDEX FK317B13C3E6B25E ON ITEM (FINISHEDSTEP);
>
> ^^^^^^^^^^^^^^^^^^^^^^^^
> These three indexes are superfluous. Drop them.
>
>
>>CREATE INDEX FOO ON ITEM (JOB, FINISHEDSTEP);"
>
>
> Depending on number of possible FINISHEDSTEP values this index
> could decrease performance too.
>
>
>>i execute the following query on this table:
>>"select count(*), finishedStep from item where job=22 group by finishedStep"
>
>
> Show us the query plan. To begin with...
>
> SY, Dimitry Sibiryakov.
>
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