Subject | Re: [firebird-support] Re: SELECT COUNT(sub_select.*) as COUNT, sub_select.user_name ... |
---|---|
Author | Martijn Tonies |
Post date | 2004-01-15T12:06:05Z |
> > SELECTbut, but ... yours doesn't work. How can it have lower
> > (select count(ss.user_name) from USER ss) as "COUNT",
> > u.user_name,
> > u.password
> > FROM USER u;
> >
> > /hb
>
> it method is lower performance
performance?
With regards,
Martijn Tonies