Subject Re: [firebird-support] Re: SELECT COUNT(sub_select.*) as COUNT, sub_select.user_name ...
Author Martijn Tonies
> > SELECT
> > (select count(ss.user_name) from USER ss) as "COUNT",
> > u.user_name,
> > u.password
> > FROM USER u;
> >
> > /hb
>
> it method is lower performance

but, but ... yours doesn't work. How can it have lower
performance?

With regards,

Martijn Tonies