Subject | Re[2]: [firebird-support] Firebird cache |
---|---|
Author | Alexander Tabakov |
Post date | 2003-07-25T15:52:40Z |
Hello Helen,
5 NUMERIC(18,0)
3 TIMESTAMP
2 VARCHAR(10)
My row structure will be: 5*64 + 3*64 + 20*1 = 212 bytes * 125 % = 265
bytes meaning that a page size of 1024 bytes will be perfectly OK.
Did I get you right?
--
Best regards,
Alexander mailto:saho@...
>One that's about 125% of the size of the largest row structure that isDoes it mean that if I have a frequently accessed table with:
>accessed frequently, or about 125% of a clean multiple of the largest row
>structure (counting the size of the blob-id but not the size of the actual
>blobs). Avoid very large varchars (use blobs instead) since the maximum
>size of a page is 16 Kb, and you want to minimise the number of page reads.
5 NUMERIC(18,0)
3 TIMESTAMP
2 VARCHAR(10)
My row structure will be: 5*64 + 3*64 + 20*1 = 212 bytes * 125 % = 265
bytes meaning that a page size of 1024 bytes will be perfectly OK.
Did I get you right?
--
Best regards,
Alexander mailto:saho@...