Subject | RE: [ib-support] Re: FB slow |
---|---|
Author | Wilson, Fred |
Post date | 2002-07-15T14:21:17Z |
<Snip from original message>
"
Think of an user editing a record, posting it, not
ending the transaction, and changing it again.
"
If you are relying on the user for transaction control (starting and
commiting transaction), via the client application, you're setting yourself
up for some nasty, nasty times, at least in a multi-user environment with
either IB or FB..
Best regards,
Fred Wilson
SE, Bell & Howell
fred.wilson@...
-----Original Message-----
From: Adrian Roman [mailto:aroman@...]
Sent: Sunday, July 14, 2002 12:48 AM
To: ib-support@yahoogroups.com
Subject: Re: [ib-support] Re: FB slow
for something that's a requiement for a DBMS.
And I know that' sometimes it happens to modifiy the same record twice in a
single transaction. Think of an user editing a record, posting it, not
ending the transaction, and changing it again.
changed in current transaction, so it's changing only the current record.
Adrian Roman
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"
Think of an user editing a record, posting it, not
ending the transaction, and changing it again.
"
If you are relying on the user for transaction control (starting and
commiting transaction), via the client application, you're setting yourself
up for some nasty, nasty times, at least in a multi-user environment with
either IB or FB..
Best regards,
Fred Wilson
SE, Bell & Howell
fred.wilson@...
-----Original Message-----
From: Adrian Roman [mailto:aroman@...]
Sent: Sunday, July 14, 2002 12:48 AM
To: ib-support@yahoogroups.com
Subject: Re: [ib-support] Re: FB slow
> I don't want to waste a lot of time in conjecturing this, since it's notBecause if it's slow in a situation like this one, I could expect to be slow
> something that would (should) be done to production data and wouldn't be a
> requirement for any transaction-capable DBMS. Why is it an important test
> for you?
for something that's a requiement for a DBMS.
And I know that' sometimes it happens to modifiy the same record twice in a
single transaction. Think of an user editing a record, posting it, not
ending the transaction, and changing it again.
> How would the engine know that? It still has to locate each delta recordIt does not need to locate each delta record, since it's changing data
> by walking both the cache and the original versions. On your first pass,
> it attacks the data in natural order; on subsequent passes it has to
> compare two sets of data, each with its own natural order. When a query is
> slow, the time cost is a matter of navigation, not the time it takes to
> alter data.
changed in current transaction, so it's changing only the current record.
Adrian Roman
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