Subject | Re: [ib-support] Subtract two TimeStamp-Fields |
---|---|
Author | Ann W. Harrison |
Post date | 2001-02-26T15:14:48Z |
At 02:51 PM 2/26/2001 +0100, guido.klapperich@... wrote:
a timestamp from a timestamp gives a number of days.
This worked for me:
SQL> create table foo (foots timestamp, foot time, food date, fooi double
precision);
SQL> commit;
SQL> insert into foo values ('now', '11:11:11.123', 'today', NULL);
SQL> select * from foo;
FOOTS FOOT FOOD FOOI
========================= ============= =========== =======================
2001-02-26 10:07:55.0000 11:11:11.1230 2001-02-26 <null>
SQL> select cast ('now' as timestamp) - foots from foo;
0.000590277
SQL> select cast ('12:00:00.000' as time ) - foot from foo;
2928.8770
SQL> select cast (cast ('now' as timestamp) - foots as numeric (9,3)) from foo;
0.003
Regards,
Ann
www.ibphoenix.com
We have answers.
>I have two fields in a tableSubtracting a time from a time gives a number of seconds. Subtracting
>Start TimeStamp (for example 19.02.2001 8:00)
>End TimeStamp (for example 20.02.2001 9:00)
>and I want the duration between these two fields. I tried something like
>
>that
>cast ((End-Start) as Numeric(9,3))
>to get the seconds, that has gone by between these two points. But I get
>
>an conversion error. Can anybody help me.
a timestamp from a timestamp gives a number of days.
This worked for me:
SQL> create table foo (foots timestamp, foot time, food date, fooi double
precision);
SQL> commit;
SQL> insert into foo values ('now', '11:11:11.123', 'today', NULL);
SQL> select * from foo;
FOOTS FOOT FOOD FOOI
========================= ============= =========== =======================
2001-02-26 10:07:55.0000 11:11:11.1230 2001-02-26 <null>
SQL> select cast ('now' as timestamp) - foots from foo;
0.000590277
SQL> select cast ('12:00:00.000' as time ) - foot from foo;
2928.8770
SQL> select cast (cast ('now' as timestamp) - foots as numeric (9,3)) from foo;
0.003
Regards,
Ann
www.ibphoenix.com
We have answers.